A ball is thrown vertically upwards. it returns 6s later. calculate:(1)the greatest height reached by the ball, and(2) the initial velocity of the ball
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Answered by
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hi friend
here's your answer looking for
so, to reach Highest point
t = 3sec
v= 0m/s
a=-10 m/s^2
so, v=u+ at
0 = u +(-10)3
u= 30m/s
so, intial velocity = 30m/s
s= ut + 1/2at^2
s= 30×3+1/2×(-10)(3)^2
s=90-45=45 m
hence , height = 45 m
and, intial velocity = 30 m/s
hope it's helpful to you
From brainly star Amaytripathi19
here's your answer looking for
so, to reach Highest point
t = 3sec
v= 0m/s
a=-10 m/s^2
so, v=u+ at
0 = u +(-10)3
u= 30m/s
so, intial velocity = 30m/s
s= ut + 1/2at^2
s= 30×3+1/2×(-10)(3)^2
s=90-45=45 m
hence , height = 45 m
and, intial velocity = 30 m/s
hope it's helpful to you
From brainly star Amaytripathi19
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Explanation:
45 m and 30 ms‐¹ are the answers
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