Question

A ball is thrown vertically upwards. It returns 6s later. Calculate: (i) the greatest height reached by the ball, and (ii) the initial velocity of the ball. (Take g=10m/s^ 2 )

Please give ma a sensible answer. I'll mark you as brainliest.​

Answer 1

Answer:

Explanation:

SEE IF A BALL RETURNS 6 SECONDS LATE MEANS IT IS TAKING TIME TO GO AS WELL AS COMING BACK TO GROUND WHICH ARE BOTH EQUAL

SO MEANS IT HAS TAKEN 3SECONDS TO GO UP

=> USING

v = u + at

0 = u - 10 x 3       [ since acceleration is in opposite direction while moving up]

u = 30m/s = initial velocity

so max height =

$v^{2}$ = $u^{2}$ +2as

0 = 900 - 2 x 10 x S

=> S = 45 m

THANK YOU

Answer 2

Answer:

I know that you are not sameer