Question

A ball is thrown vertically upwards. It returns 6s later. calculate the greatest height achieved by the ball and the initial velocity of the ball. (g=10m/s²).

Answer 1

Time will be 3 secs as body will attain its maximum height at this time and then will start falling downward. Now, Time, t = 3 secs Final velocity, v= 0 g = 10m/s². First we will find out initial velocity: v= u+gt 0= u+ (-10)x 3 u= 30 m/s Now, height=? v²-u²= 2gh 0²-30²= 2x(-10)xh Solving it we get the height= 45 metres