A ball is thrown vertically upwards .It rises to a height of 125 m and comes back to the thrower
Answers
Answered by
2
Answer:
The equation is given as v
2
−u
2
=2as.
where,
v = final velocity,
u = initial velocity,
a = acceleration due to gravity, 10m/s
2
,
s = h = height traveled.
Therefore, we can find u with above info. In this case, v = 0 at the top of the path.
0−u
2
=2×10×5=10m/s.
Hence, the initial velocity of the ball was 10 m/s.
Answered by
1
so what uh wanna know?
the distance that ball's covers?
then,
- distance = 35m +35m
= 70m
and
- displacement= 0
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