Question

A ball is thrown vertically upwards. It rises to a height of h m in 2.5 s and then comes back to the thrower. Calculate
i) its initial speed,
ii) the time for which it remained in the air.
iii) the distance travelled and the displacement of the ball.

Answer 1

Explanation:

1. V = U + at

0 = U - 9.8 x 2.5

U = 9.8 x 2.5 m/s

2. T = time of ascent + time of descent

=2.5 +2.5 =5s

3. distance = 2h, displacement= 0