A ball is thrown vertically upwards. Its distance s from a fixed point
varies with time t according to the following graph. Calculate velocity
of projection of the ball.
(A) 10 m/s
(B) 20 m/s
(C) 30 m/s
(D) 50 m/s
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Answer:
The correct answer is A
10 m/s
Explanation:
v2=u2−2gh
As we know that velocity is the total distance covered in a certain period of time. v= d/t
where 'd' is distance and 't' is the time period.
so applying this formula:
As we know that after reaching maximum height, the velocity of the ball becomes zero.
Here is the solution:
0=(10)2−2×10×h2
∴h=20020=10m/s
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