A ball is thrown vertically upwards such that when it reaches half the maximum height it was a velocity of 7 metre per second what is the maximum height attained by the ball?
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Answer:
The answer is 5 meters.
Step-by-step explanation:
If a body is thrown vertically upwards with a velocity of 'u' m/s and the body reaches to a maximum height of 'h' meters. Where v = 0 is the velocity of the body at the maximum height.
Then from the equations of motion we get ,
v² = u² - 2gh [ 'g' being the acceleration due to gravity ]
⇒ 0² = u² - 2gh
⇒ u² = 2gh → (1)
In this case , velocity of the body at the half of the maximum height ( h/2 ) is, v = 7 m/s.
Then , v² = u² - 2g( h/2 )
⇒ 7² = u² - gh
⇒ u² - gh = 49
⇒ 2gh - gh = 49 [ from (1) ]
⇒ gh = 49 ⇒ 9.8 × h = 49 ⇒ h = 5 meters.
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