Question

a ball is thrown vertically upwards. the speed of the ball was 10m/s. Find the velocity and acceleration of 1s after it is thrown.

Answer 1

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Let H be the maximum height of the ball. When, the ball is reached one half of the maximum height , then

$u = 10m/s,v = 0m/ {s}^{2} \: and \: h = H/2( \: remaining \: height),</p><p>$

by using,

$= > \: \: \: \: \: {v}^{2} = {u}^{2} - 2gh$

$= > \: \: \: \: \: {0}^{2} = {10}^{2} - 2 \times 10 \times ( H/2)$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or$

$H = 100/10 = 10m$

hope this will help you...

-3idiots29