Question

A ball is thrown vertically upwards. The speed of the ball was 10 m/s when it had reached one half of its maximum height. Find the velocity and acceleration 1s after it is thrown.

Answer 1

Explanation:

Answer

Let H be the maximum height of the ball .

When , the ball is reached one half of the maximum height , then

           u=10m/s,v=0m/s,g=10m/s2 and h=H/2 (remaining height) ,

by using ,    

              v2=u2−2gh 

              02=102−2×10×(H/2)

or           H=100/10=10m