a ball is thrown vertically upwards. the velocity at one third of the maximum height is 8m/s. The velocity with which the ball is thrown
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10 m/s must be the initial velocity of the ball
abhi63715:
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let maximum height = 3x meter
so, v at xmetr = 8m/s
a = -9.8m/s²( gravitational )
by__ v² = u²+2as(at x metrs)
u² = 8 +19.6x m/s
by - v²=u²+ 2as (at highest point)
x = 8/40.2 m
so, speed of body at initial point
= 12m/sec. ANS..
so, v at xmetr = 8m/s
a = -9.8m/s²( gravitational )
by__ v² = u²+2as(at x metrs)
u² = 8 +19.6x m/s
by - v²=u²+ 2as (at highest point)
x = 8/40.2 m
so, speed of body at initial point
= 12m/sec. ANS..
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