Physics, asked by Shreyarajput111, 1 year ago

A ball is thrown vertically upwards upto height h . the ball returns back to the thrower. What is the distance and displacement covered by the ball ?

Answers

Answered by Anonymous
17
Here the height = h

Therefore the u = 0

S = UT + 1/2 at²
= 0 + 1/2 at²

Therefore the distance = 1/2 at²
And acceleration = v - u/t
=v- u = a*t
Displacement = a*t

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Answered by rakeshmohan73
0

The Displacement will be 0.

According to the question,

Here the height = h

Therefore the u = 0

S = UT + 1/2 at²

= 0 + 1/2 at²

Therefore the distance = 1/2 at²

And acceleration = v - u/t

=v- u = a*t

Displacement = a*t

However the displacement will be 0 as the ball after covering a distance comes back to its initial point and displacement is the shortest distance between initial and final point.

Here the Initial and final position are same so displacement will be zero.

More knowledge related to Displacements.

https://brainly.in/question/1210804?msp_srt_exp=4

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