A ball is thrown vertically upwards with a speed of 0.5 m/s. How high will will it go before it begins to
fall? How long will it take to reach that height
Answers
Answered by
0
Answer:
t = 0.5/9.8 = 0.051 s = 52 ms.
Answered by
0
Answer:
given:
u=0.5m/s
g=9.8m/s^2(it is taken to be negative since body is going against the gravity )
v=0
s=xv^2-u^2=2gs
(0)^2-(0.5)^2=2(9.8)S
-(0.5*0.5)=-2*9.8*S
s=0.5*0.5/2*9.8=0.012m is answer
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