Question

A ball is thrown vertically upwards with a speed of 19.6 m/s from the top of a tower returns to earth in 6 sec,then height of the tower is?​

Answer 1

u= 19.6m

t= 6s

g = -9.8 m/s^2

displacement of the ball = -h

s=ut+1/2at^2

-h = 19.6×6+(-9.8)×36/2

= 58.8metres

hope it helps u...

Answer 2

u = 19.6 m/s

t = 6sec

g = 9.8 m/s^2

h = ?

s = ut + 1/2 at ^2

-s (height) = - 19.6 × 6+(-9.8) × 36/2

h = 58.8 m