a ball is thrown vertically upwards with a speed of 20m/s from the top of a tower stricks the base of the tower in 6s . find the height of the tower (g=10m/s^2)
Dhinu:
Right ans. is 80 m.....
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Let the height of the tower = h
Now by second equation of motion
S = ut - 1/2gt^2
Take upword plus sign and downward minus sign
Here we take s = - h
U = 20
t =6
- h = 20*6 - 1/2*10*6*6
h = 36*5 - 120=180 - 120=60m
Which is the height of the tower
I hope it's help
Now by second equation of motion
S = ut - 1/2gt^2
Take upword plus sign and downward minus sign
Here we take s = - h
U = 20
t =6
- h = 20*6 - 1/2*10*6*6
h = 36*5 - 120=180 - 120=60m
Which is the height of the tower
I hope it's help
ya ! thanks!
and sorry for late reply .. wo me maths ki class me tha !
and .... i am really sorry for that ... i was just ... really gone insane... i am sorry!
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