Question

A ball is thrown vertically upwards with a speed of 30m/s. At the same time another ball is thrown vertically downwards with a speed of 10m/s from the top of a building of height 100m. Find the position where they will meet ?



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Answer 1

Step-by-step explanation:

The distance covered is given as

s

1

=20t+5t

2

s

2

=30t−5t

2

s

1

+s

2

=150⇒150=50t⇒t=3s

Hence, the time after which both the balls will meet is 3 s.

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