A ball is thrown vertically upwards with a speed of 49 m/s calculate 1) maximum height of the ball 2) total time taken by the ball to reach the earth surface
Answers
Answered by
3
hope this answers will help you
Attachments:
stuti49:
negative height means the opposite direction
so it can be possible
height is dist and dist is not a vector quantity
its scalar
it cant be neg
and doesn't have any direction
distance is always measured positive
it is just an assumption
u have done the same thing in the question
why have u taken a as neg
Answered by
3
u=49 m/s
v=0(at max. height)
a =-10 m/s(considering upwards direction to be positive)
v^2-u^2=2as
0 - 49*49= 2*-10*s
s=120.5 m
time taken to reach max. height
v=u+at
0=49-10t
t=4.9 s
therefore to reach back to ground time taken =
time taken to reach max. height *2
= 4.9*2
=9.8 s
u have also used acc as -10 and i use it at -9.8
Similar questions