A ball is thrown vertically upwards, with a speed of U. Equation of height as a function of t, is given by h = ut - (1/2)g(t^2).
Find:
1. Time to reach maximum height (t)
2. Maximum height reached (h).
g is the acceleration due to gravity. Answer is desired in terms of g (dont take its value).
Answers
Answered by
1
See the attachments
Mark me as brain list if u get this
Attachments:
Similar questions