Question

A ball is thrown vertically upwards with a velocity fo 10 m/s. if g is

10m/s2

, then calculate

(i) height it reaches

(ii) time taken to return back​

Answer 1

Given ,

• Initial velocity (u) = 10m/s
• Acceleration due to gravity = 10m/s²

________________________

i) Height it reaches :-

Using ,

♦ H = u²/2g

Here ,

• u = 10m/s
• g = 10m/s²
• H = ?

⇒ H = 10²/2(10)

⇒ H = [ 100/20 ]

⇒ H = 10/2

⇒ Height = 5m

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ii) Time taken to return back :-

Using ,

♦ v = u + gt

Here ,

• v = 10m/s
• u = 0m/s [since it starts from rest when it is in air for some time ]
• g = 10m/s²
• t = ?

⇒ 10 = 0 + 10 × t

⇒ 10 = 10t

⇒ t = 10/10

⇒ Time = 1s

Time cannot be negative

⇒ Time = 1s

Answer 2

Answer:

Given :-

• A ball is thrown vertically upwards with a velocity of 10 m/s.

To Find :-

• What is the height.
• What is the time taken.

Formula Used :-

➤ To find height we know that,

★ h = u²/2g ★

➤ To find time taken we know that,

✯ v = u + gt ✯

where,

• v = Final velocity
• u = Initial velocity
• g = Acceleration due to gravity
• h = Height
• t = Time taken

Solution :-

➙ To find height,

Given :

• Initial velocity = 10 m/s
• Acceleration due to gravity = 10 m/s²

According to the question by using the formula we get,

⇒ h = (10)²/2(10)

⇒ h = 100/20

⇒ h = 10/2

➠ h = 5 m

∴ The height of the ball is 5 m .

➙ To find time taken to return back,

Given :

• Initial velocity = 10 m/s
• Acceleration due to gravity = 10 m/s²
• Final velocity = 0 m/s

According to the question by using the formula we get,

↦ 0 = 10 + 10 × t

↦ 0 = 10 + 10t

↦ 0 - 10 = 10t

↦ - 10/- 10 = t

↦ 1 = t

➠ t = 1 seconds

∴ The time taken to return back is 1 seconds .