Question

A ball is thrown vertically upwards with a
velocity of 10m/s. The time taken to reach
maximum height is:(hint: take g=10m/s2)​

Answer 1

Answer:

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Answer 2

Answer:

A ball is thrown vertically upwards with a  velocity of 10m/s. The time taken to reach  maximum height is $1\ s$

Explanation:

We can use the first and third equation of motion to solve this problem.

• According to the first equation of motion,

        $\mathrm{v}=\mathrm{u}+\mathrm{at}$            ...(1)

• According to the third equation of motion,

        $\mathrm{v}^{2}-\mathrm{u}^{2}=2 \mathrm{aH}$     ...(2)

Where

u - Initial velocity of the object

v - Final velocity of the object

a - acceleration

t -  time taken

From the question,

$u = 10\ m/s$

$v =0$

$a = g =- 10\ m/s^2$  (since ball throw vertically upward)

Substitute all these values into equation (2)

$0-(10)^{2}=2 \times(-10) \times \mathrm{H}$

$H = \frac{10^{2} }{20} = 5$

Now consider equation(1),

$0=10-10 \mathrm{t}$

$t = 1 \ s$