Question

A ball is thrown vertically upwards with a velocity of 10ms-1

from the top of a tower. The height

of the point from where the ball is thrown is 15.0m from the ground. What is the maximum

height reached by the ball? Take as g= 10ms-2

.​

Answer 1

Explanation:

Taking downward direction to be positive.

Initial velocity u=−10 m/s

Final velocity v=30 m/s

Let the height of the tower be H.

Acceleration a=g=10 m/s

2

Using v

2

−u

2

=2aH

∴ 30

2

−(−10)

2

=2×10 ×H

⟹ H=40 m