A ball is thrown vertically upwards with a velocity of 20 m/s from the top of a multistory building.
The height of the point from where the ball is thrown is 25.0 m from the ground.
a) How high will the ball rise?
b) how long will it be before the ball hits the ground? Take g=10 m/s2
.
Answers
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Explanation:
u=20m/s
v=0
a=-10m/s( because the ball is moving upward)
t=v-u/a
=0-20/-10
=2 second
a) the maximum height=S=ut+1/2at^2
=20×2+-10×4/2
=40-20
=20 m
b) the time taken to touch the ground =2t
. =2×2
=4s
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