A ball is thrown vertically upwards with a velocity of 20 m/s from the top of a multistorey building.
The height of the point where the ball is thrown 25 m from the ground. How long will it be before
the ball hits the ground ? Take, g = 10 m/s^2
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2
Answer:
Time to reach maximum height can be obtained from v=u+at
0=20+(−10)t
t=2s
s=ut+0.5at
2
=20(2)+0.5(−10)(2)
2
=20m
Thus, total distance for maximum height is 45 m
s=ut+0.5at
2
45=0+0.5(10)(t
′
)
2
t
′
=3s
Total time= 3+2= 5s
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