Question

A ball is thrown vertically upwards with a velocity of 20 ms⁻¹ from the top of a tower of height 60 m. How long will it travel before it hits ground?

Answer 1

Answer:

6 seconds

Explanation:

initial velocity= 20m/s

final velocity= 0 m/s (as it will stop at ground)

given distance= 60m

So, from : 2as=v^2-u^²

a={(0^2-20^2)/2×60}m/s^2

a= -10/3 m/s^2

Now, from v=u+at

Required time=> t= v-u/a= (0-20)/(-10/3)= 6seconds..