a ball is thrown vertically upwards with a velocity of 20m/s. How much will it cover in 3s? (take g=10m/s)
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S=ut+1/2×-g×t*2=(20×3)-(1/2×10×9)=15m
snehavinod34:
okay dude...
Answered by
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so simple
given that,
u = 20m/s
a= -g = -10 m/s²
s = ?
t= 3s
by the Newton's 2nd law of motion
s= ut+1/2at²
s = 20×3 + 1/2 ×-10 × 3²
s = 60 - 1/2 90
s = 60 - 45
s = 15 metre
the answer is 15 metre
please mark it as brainliest answer if you have satisfied
given that,
u = 20m/s
a= -g = -10 m/s²
s = ?
t= 3s
by the Newton's 2nd law of motion
s= ut+1/2at²
s = 20×3 + 1/2 ×-10 × 3²
s = 60 - 1/2 90
s = 60 - 45
s = 15 metre
the answer is 15 metre
please mark it as brainliest answer if you have satisfied
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