Question

A ball is thrown vertically upwards with a velocity of 25m/s then calculate
1. the hight it reaches
2. Time taken to return back​

Answer 1

Explanation:

1. ᴜ = 25ᴍ/s

ɢ = 10ᴍ/s [ ᴛᴀᴋᴇɴ ]

ᴠ = 0ᴍ/s

ʜ = ?

2ɢʜ = ᴠ^2 - ᴜ^2

2*-10*ʜ = - 625 [ ᴠ = 0 ; ᴜ = 25^2 ]

ʜ = -625/-20

ʜ = 31.25ᴍ

2. ᴛ = ᴠ -ᴜ/ɢ

= 0 - 25 / -10

= 2.5s