Question

A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate
The Maximum height to which it reaches.

​

Answer 1

V = 49 , g = -9.8 , U = 0

2as=v^2-u^2

2×-9.8×s = 49^2-0^2

s = 2401/-19.6

s = -122.5

please follow me