Question

A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate:
the max height to which it rises.​

Answer 1

Given,

A ball is thrown vertically upwards with a velocity of 49 m/s.

To Find,

The maximum height to which it rises.

Solution,

Initial velocity (u) = 49 m/s

Final velocity (v) = 0 m/s

As the ball thrown upwards , the acceleration of gravity is negative. Therefore g = -9.8 m/s square

Let h be the maximum height the ball reaches.

Using the third equation of motion,

$v^{2} - u^{2} = 2as$

Substituting the s with h and a with g, we get the formula as,

$2gh = v^{2} - u^{2}$

2 x -9.8 x h = 0 - $(49)^{2}$

= -19.6h = -2401

h = 122.5 m

Therefore the maximum height the ball reaches when thrown in an upward direction is 122.5 m.