A ball is thrown vertically upwards with a velocity of 49 m/s. Mass of the ball is 20g.
What will be the final velocity?
What is the maximum height covered by ball?
What is the final momentum of the ball?
What kind of motion is this?
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Given:
Initial velocity of the ball (u) = 49m/s.
Velocity of the ball at maximum height (v) = 0.
g = 9.8m/s²
Let us consider the time is t to reach the maximum height H.
⇒ 2gH = v2 – u2
2 × (- 9.8) × H = 0 – (49)2
– 19.6 H = – 2401
∴H = 122.5 m
Now,
⇒ v = u + g × t
0 = 49 + (- 9.8) × t
– 49 = – 9.8t
t = 5 sec
(1) The maximum height to which the ball rises = 122.5 m
(2) The total time ball takes to return to the surface of the earth = 5 + 5 = 10 sec.
Explanation:
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