A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate the maximum height to which it rises.
(ii) The total time it takes to return to the surface of the earth
Answers
Answered by
5
Answer:
Velocity of the ball at maximum height is zero, v=0
v² −u² =2aH
0−(49)² =2×(−9.8)×H
⟹H=122.5 m
v=u+at
0=49−9.8t
⟹t=5 s
∴ Total time taken by ball to return to the surface, T=2t=10 s
Explanation:
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Answered by
7
Answer:
Given
Initial velocity(u) = 49m/s.
The velocity of the ball at maximum height (v) = 0.
g = 9.8m/s2
To find
The total time it takes to return to the surface of the Earth.
Solution
Consider a formula,
v = u + gt
0 = 49 + (- 9.8) × t
– 49 = – 9.8t
t = 5 sec
Explanation:
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