Physics, asked by BangtanXArmy0t7, 20 days ago

A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate the maximum height to which it rises.
(ii) The total time it takes to return to the surface of the earth​

Answers

Answered by sonunimbajiwakode
5

Answer:

Velocity of the ball at maximum height is zero, v=0

v² −u² =2aH

0−(49)² =2×(−9.8)×H

⟹H=122.5 m

v=u+at

0=49−9.8t

⟹t=5 s

∴ Total time taken by ball to return to the surface, T=2t=10 s

Explanation:

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Answered by leenudua
7

Answer:

Given

Initial velocity(u) = 49m/s.

The velocity of the ball at maximum height (v) = 0.

g = 9.8m/s2

To find

The total time it takes to return to the surface of the Earth.

Solution

Consider a formula,

v = u + gt

0 = 49 + (- 9.8) × t

– 49 = – 9.8t

t = 5 sec

Explanation:

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