Physics, asked by kinshuk2406, 11 months ago

A ball is thrown vertically upwards with a velocity of 49m/s. Calculate the maximum height to which it rises and the total time it take to return to surface of the earth.

Answers

Answered by aryany1234554321
3

Answer:

u=49m/s

v=0m/s

g=-9.8m/s square

T=?

v=u+at

0=49+(-9.8)×t

-49=-9.8×t

-49/-9.8=t

T=5sec

Answered by himanshupatil2327
0

Answer:

u=49m/s

v=0m/s

g=9.8m/s

3rd equation of motion

max high (S)

a) x^2 - y^2=29s

=v^2=(49)^2=2(-9.8) * S

=2401=-19.6*S

=S=240*10/19.6*10=122.5

Explanation:

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