A ball is thrown vertically upwards with a velocity of 49m/s. Calculate the maximum height to which it rises and the total time it take to return to surface of the earth.
Answers
Answered by
3
Answer:
u=49m/s
v=0m/s
g=-9.8m/s square
T=?
v=u+at
0=49+(-9.8)×t
-49=-9.8×t
-49/-9.8=t
T=5sec
Answered by
0
Answer:
u=49m/s
v=0m/s
g=9.8m/s
3rd equation of motion
max high (S)
a) x^2 - y^2=29s
=v^2=(49)^2=2(-9.8) * S
=2401=-19.6*S
=S=240*10/19.6*10=122.5
Explanation:
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