A Ball is thrown vertically upwards with a velocity of 49m/s . calculate
1) the maximum height to which it rises
2) the total time it takes to return to the surface of earth
( g=10m/s^2)
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Explanation:
u = 49
v = 0
v = u - at
0 = 49 - 10* t
10t = 49
t = 4.9s
Total time = 4.9* 2
= 9.8s
v² = u² - 2as
0 = 49² - 2*10*s
20s = 2401
s = 120.05m
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