Question

a ball is thrown vertically upwards with a velocity of 49m/s . calculate the maximum lenght upto which it rises​

Answer 1

Answer:

Explanation:

u= 49 m/s

g= 9.8 m /s^2

Let us considered the time taken is t to reach the maximum height H.

Consider the formula,  2gH = v2 – u2

=>2 × (- 9.8) × H = 0 – (49)2

=>– 19.6 H = – 2401

H = 122.5 m

Answer 2

Answer:

Given Initial velocity of ball, u=49 m/s

Let the maximum height to reach that height be

Assumption: g=9.8 m/s^2

Velocity of the ball at maximum height is zero,v=0

v^2 - u^2 = 2aH

(0)^2 - (49)^2 =2×(−9.8)×H

⟹H=122.5 m

Explanation:

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