Question

a ball is thrown vertically upwards with a velocity of 49m/s. calculate its maximum height to which it rises​

Answer 1

Answer:

According to question we have

Explanation:

u =49 m/s

v = 0 m/s

g= -9.8 m/s^2

now,

v^2 - u^2 =2gs

(०)^2 - (49)^2 = 2×-9.8 ×s

-2401 = - 19.6 ×s

- 2401 /- 19.6 =s

122.5 = s