Question

A ball is thrown vertically upwards with a velocity of 49ms–¹ calculate the maximum height to which it rises..​

Answer 1

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Given Initial velocity of ball, u=49 m/s

Let the maximum height reached and time taken to reach that height be H and t respectively.

Assumption: g=9.8 m/s2 holds true (maximum height reached is small compared to the radius of earth)

Velocity of the ball at maximum height is zero, v=0

v2−u2=2aH                          

0−(49)2=2×(−9.8)×H        

⟹H=122.5 m              

v=u+at

0=49−9.8t            

⟹t=5 s

∴ Total time taken by ball to return to the surface, T=2t=10 s

Answer 2

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