Question

A ball is thrown vertically upwards with a velocity of 5 m/s. What will be the maximum height this ball will reach?

Answer 1

Answer:

MAXIMUM HEIGHT IS 1.25m

Explanation:

s=u^2/2g

s=5^2/2×10

s=25/20

s=1.25 m

Answer 2

Given,

v = 5 ms^-1

a = 10 ms^-2

u = 0 ms^-1

s = ?

Apply third equation of motion here,

v^2 = u^2 + 2as

(5)^2 = (0)^2 + 2 × 10 × s

25 = 0 + 20 × s

25 / 20 = s

1.25 m = s

Hope this helped you dear...