Question

A ball is thrown vertically upwards with a velocity of 50m/s. Calculate the maximum height to which it rises.Take g = 9.8m/sec square

Answer 1

SOLUTION :-

When the Ball is thrown vertically upwards, then the Velocity of the Ball keeps on decreasing because of the Force of Gravity of Earth acting on it in the Downward Direction; So, the Acceleration produced in the Ball is Negative and hence, it is to be written with a Minus sign $[(-9.8)m/s^2]$

GIVEN :-

Initial Velocity (u) = 50 m/s

Final Velocity (v) = 0 m/s

Acceleration (a) = $-9.8m/s^2$

TO FIND :-

Distance Travelled (Here, the Height Attained) (s) = x m

Using the Third Equation of Motion, (i.e.), $v^2 = u^2 + 2as$, we get -

$=> 0^2 = 50^2 + 2\:(-9.8)(s)\\\\=> 0 = 2500 + (-19.6)s\\\\ 19.6s = 2500\\\\Therefore\:s = \frac{2500}{19.6} = 127.5 m$

Thus, the Height Attained by the Ball is 127.5 m

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