A ball is thrown vertically upwards with a velocity of 9.8 m/s. Find its velocity after 1 second. [ Take g = 9.8 ms-2]
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Answer:
2 second
Explanation:
Given,
Take initial velocity u=9.81m/s
Acceleration is downward a=−g=−9.81m/s
2
When the body come to the ground, it has equal velocity in magnitude but opposite in direction.
Final velocity v=−u
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Apply kinematic equation
v=u+at
−u=u−gt
t=
g
2u
=
9.81
2×9.81
=2sec
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