Question

A ball is thrown vertically upwards with an initial velocity of 56m/s. Calculate:- (i) The maximum height attained (ii) The time taken by it before it reaches the ground again [here g=9.8m/s²​

Answer 1

Answer:

The maximum height attained is 160m

time taken before it reaches the ground is 5.7s

Explanation:

For Maximum Height

   v² = u²+2as

   0² = 56² + 2*-9.2*s

   -56² = -19.6s

   56² = 19.6s

   3136 = 19.6s

   3136/19.6 = s

   s = 160m

For Time Taken Before to reach the ground

u =0

a = 9.8m/s

s = 160m

s= ut+at²/2

160 = 9.8*t²/2

160 = 4.9t²

160/4.9 = t²

32.65 = t²

t = 5.7s