Question

A ball is thrown vertically upwards with an initial velocity of 100 m/s. After how much time will it return? Draw time-velocity graph for the ball and find from the graph: i) Height attained by the ball? ii) Height of the ball after 15 seconds?​

Answer 1

Answer:

B

375m

Explanation:

Initial velocity of the ball u=100 m/s

Acceleration of the ball a=−g=−10 m/s

2

Using v=u+at

∴ v=100−10t

Thus v−t graph is a straight line intersecting the t axis at t=10 s

Also v

∣

∣

∣

∣

∣

t=15

=100−10(15)=−50 m/s

2

Height (displacement) of the ball is equal to the area under the curve during 0<t<15

∴ h=

2

1

×100×10−

2

1

×(15−10)×50=375 m

Answer 2

Answer:

height =375 m

hope it helps u !