a ball is thrown vertically upwards with the speed of 19.6m/s-1from the top of the tower it returns to the earth in 6 seconds find the height of the tower
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v = u + at
v = 19.6 + 9.8*6
v = 78.4m/s
H = (v² - u²)/(2a)
H = (78.4²- 19.6²) / (2*9.8)
H = 294m
v = 19.6 + 9.8*6
v = 78.4m/s
H = (v² - u²)/(2a)
H = (78.4²- 19.6²) / (2*9.8)
H = 294m
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