A ball is thrown vertically upwards with the speed of 30m/s . It returns back to the hands of the thrower after 6s. Calculate the maximum height attained by the ball .[Use g =10m per second ]
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find angle with which it is thrown by using time of flight given
then find maximum height by formula speed*speed*sin of angle*sin of angle divided by g
then find maximum height by formula speed*speed*sin of angle*sin of angle divided by g
sahilbaria516:
I can't understand the answer shiny
6=30*sinx
sinx=1/5 height=30*30*1/25/10 =18/5
Tell me properly shiny
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