a ball is thrown vertically upwards with velocity 50m/s at t=0 . then find distance travelled from t=0 to t=8 s
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Explanation:
u=50m/s
a=-10
t=0
so,we know that,
s=ut+1/2at^2
s=50×0+1/2×(-10)×0
s=0
again,u=50m/s , a=-10 , t=8sec
s=ut+1/2at^2
s=50×8+1/2×-10×8^2
s=400-320
s=80m
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