Question

A ball is thrown vertically upwards with velocity of 25m/s. Consider g = 10m/s square. Calculate the maximum height to which it rises abd the total time it takes to return to the earth's surface.

Answer 1

Answer:

initial velocity of ball=25m/s.

acceleration due to gravity=10m/s.

final velocity=0m/s

we have.

v=u+gt.

0=25m/s+10m/s×t

-10m/s×t=25m/s

t=25m/s/-10m/s

t=5/2s

then,

we have.

s=ut+1/2gtsquare

s=25m/s×5/2s+1/2×10m/s×(5/2) square

s=125/2+1/2×10×(25/4)

s=62.5+5×(25/4)

s=62.5+125/4

s=62.5+31.25

s=93.30

Answer 2

Answer:

31.25 m

Explanation:

$h(max) = (u {}^{2} sin {}^{2} x) \div 2g$

x=90°=1

h=(25*25)/20

h=31.5m