Question

a ball is thrown vertically upwards with velocity u. Find the expression for the maximum height attained by it.​

Answer 1

Explanation:

From third equation of motion,

v

2

=u

2

−2gS

wherev = final velocity = 0 , u = initial velocity , S = distance

0=u

2

−2gS

u

2

=2gS

S=

2g

u

2

Answer 2

Kinetic energy of ball

$ke = \frac{1}{2} mu{}^{2}$

if energy is conserved

$ke = pe \\ i.e \\ \frac{1}{2} mu {}^{2} = mgh$

maximum height attained by ball

$\huge \it \underline{h = \frac{ u {}^{2} }{2g}}$