Question

a ball is thrown vertically upwards with velocity u. find the time taken by the ball to reach at maximum height.​

Answer 1

$\sf{\large{\underline{\underline{EXPLANATION:}}}}$

★Given,

• Initial velocity of the ball=u

• Final velocity of the ball,v=0m/s(since it reaches at maximum height and comes to rest)

• Gravitational acceleration,a=-g=-9.8m/s²

★To find,,

• Time taken by the ball to reach at the max. height.(i.e.,t=??)

★By using 1st eq. of motion,,

$\sf{\boxed{v=u+at}}$

$\sf{\implies{0=u+(-9.8)t}}$

$\sf{\implies{-u=-9.8t}}$

$\sf{\implies{\frac{u}{9.8}=t}}$

Therefore,, time taken by the ball,

$\sf{\boxed{t=\frac{u}{9.8}}}$

$\rule{200}2$

❣️❣️★Hope it helps★❣️❣️