Question

a ball is thrown vertically upword with an intial velocity of metal per second . calculate maximum height attained by the ball and the time.​

Answer 1

Explanation:

Solutions:

initial velocity of the ball in meter per second be = u m/s

let the time taken be = t sec

so,

we know that

s= ut+ (at^2)/2

s= u×t + (-9.8× t^2)/2

s = {2ut +(-9.8t^2)}/2

s= {2ut-9.8t^2}/2

so maximum height = (2ut-9.8t^2)/2 meters

so ,

we know that,

time = distance ÷ velocity

t= {(2ut-9.8t^2)/2÷ u} second

so, time require is{(2ut-9.8t^2)/2÷ u} second