a ball is thrown veticaly upward from ground with speed 40m/sec . to what height the ball goes
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Answer:
12.4 sec
Step-by-step explanation:
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Motion in a Straight Line
Problems Based on Free Fall
A ball is thrown vertically...
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Asked on December 26, 2019 by
Imran Mandavkar
A ball is thrown vertically upward from ground with speed 40m/s. It collides with ground after returning. Find the total distance traveled and time taken during its bouncing. (e=0.5) (g=10 m/s
2
)
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ANSWER
Distance traveled before first collision =
2g
u
2
×2
=160m
Time taken =
10
2×160
=
32
sec
After collision velocity will reduce to half because velocity of separation=velocity of approach
Distance traveled before third collision =(
2
u
)
2
×
2g
2
=40m
Time taken =
2
3
2
Total distance after infinite collision =160(1+
4
1
+
16
1
......∞)
=160(
3
4
)m=213.3m
Total time taken=
32
[1+
2
1
+
2
2
1
....∞]
=
32
(
2
−1
2
)
=12.4sec
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