Question

a ball is thrown with 20m/s at an angle of 60 with x-axis.The horizontal velocity of the body at top postion is?

Answer 1

Hey...!!

As we know the horizontal velocity at any point of the projectile in horizontal projectile is..
v= v cos(theta)

So v = 20 × 1/2 = 10.....as cos (60°)= 1/2

Hope this helps you.... ☺️☺️

Answer 2

Solution:-

given by :-

》a ball is thrown with 20m/s

》angles = 60 with x -axis

》Velocity along x-axis = ux = u cos θ

》 = ux = 20×cos60

》 = 20×1/2

》 = 10m/s