Question

a ball is thrown with a speed of 17m/s at a projection angle of 58° above the horizontal. determine the time of flight of projectile and the maximum height attained.​

Answer 1

Explanation:

Given : u=20 m/s θ=30

o

g=10 m/s

2

We get sinθ=sin30

o

=

2

1

Maximum height reached H=

2g

u

2

sin

2

θ

=

20

20×20×(

2

1

)

2

=5m