A ball is thrown with a velocity of 20m/s from the top of the tower of height 25m .1=find how high will the ball rise.2=time taken by the ball in touching the ground
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Answer:
Explanation:
v = 20 m/s H = 25 m
S = ball rise (height of ball covered from tower in upward direction)
S =
S = g=10 m/ s^2
S =
S = 20 m
Maximum height from ground = 25 + 20 == 45 m
T = total time to reach the ground
T =
here u/g is the time of ascent and the other under root value is the time of descent
T =
T = 5 sec
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